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Physics 20 Online
OpenStudy (anonymous):

A person with a mass of 74 kg and a volume of 0.079 m3 floats quietly in water. (a) What is the volume (m^3) of the person that is above water? (b) If an upward force F is applied to the person by a friend, the volume of the person above water increases by 0.0019 m3. Find the force F (N).

OpenStudy (anonymous):

It should be the same, equal and opposite. I think...

OpenStudy (anonymous):

So .079 and then .0809

OpenStudy (anonymous):

Person floats when the volume of water displaced has a weight equal to his own. 74kg person displaces 0.074m3 of water, thus 0.079m3-0.074m3=0.005m3 is above water. The friend must supply the weight of water no longer displaced. 0.0019m3 of water has a mass of 1.9kg, which corresponds to (9.8N/kg)(1.9)=18.6N.

OpenStudy (anonymous):

That sounds better than mine....

OpenStudy (anonymous):

Thank you very much!

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