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balancing equation ?
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\[Al(s) + HBr (aq) \rightarrow AlBr _{3} + H _{2}\]
so you need an equal amount of hydrogen, bromine and aluminum on both sides. As you can see on the left you have only one Br but on the right you have 3, and u have 2 H's on the right and only 1 on the left. Thus you have to put coefficients in front of the molecules that you want more of. You might start with putting a 3 in front of the HBr so you would have 3 Br...but then also change the H2 on the right side to match. That is the general idea.
did that make sense?
yea it does thanks :)
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