Question

A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 for g and 3.14 for π. If you enter your answer in scientific notation, round the decimal value to two decimal places. Use equivalent rounding if you do not enter your answer in scientific notation.) r=6.6, h=3.3

Answer 1

it is spherical

Answer 2

W = gπr^2(integral {hdh } = gπr^2(h^2)/2
I'll leave it to you to plug in the proper values and round off the answer.
In the future, it would be nice if you attach the proper unit to the various measurements.
e.g. h=1.5 is it measured in inches, meters, yards ?
I'll leave it to you to convert things to the proper units to make W = gπr^2(h^2)/2 correct.

Answer 3

hope this help click best response

Answer 4

do this help u @Jmnz

Answer 5

thanks and i forgot to mention it is in meters

Answer 6

wattttttttttttttttt

Answer 7

Is this a cylindrical tank of water?

Answer 8

no it is a spherical tank

Answer 9

https://www.webassign.net/scalcet/6-4-022alt.gif

Answer 10

ohh

Answer 11

OK then the work required W is equal to the total mass of water multiplied by the total distance to pump that water from the bottom of the tank to the top of the spout (assuming there's a hose going down the spout to the bottom)

So we have W = mgd where m= mass of water, g= 9.8 and d=r+h

m = Volume x density of water
m= (4/3)pi.r^3 x 1000

I'll let you do the rest

Answer 12

ok thanks but i do not understand how to do the rest.

Answer 13

to get the work done W you just multiply mass x g x d

the mass is (4/3) x pi x r^3 x 1000
g = 9.8 and d = r+h and you know r=3.3 and h=6.6

you follow now?

Answer 14

yea i follow now... thank you

Answer 15

OK, good. the final answer will be in Joules