Question

@ganeshie8

Answer 1

I was gonna go bed but I will solve one last problem!

Answer 2

We have position s(t), velocity is the rate of change of position, so take the derivative of the position function.

Answer 3

OK

Answer 4

s'(t)=-32(t-2)

Answer 5

i am subbing in for gaaneshi

Answer 6

-32(3-2)
-32(1)
s'(3)=-32

Answer 7

due to the acceleration of the earth when the ball is thrown up with a positive velocity there will occur a point where the negative accleration will switch the positive velocity to zero then to negative veloicty at this point the ball will start to travel downward so you want to know the exact point where it stops travelling up to down
that point where it goes from +'ve velocity to -'ve velocity there is a zero velocity inbetween so u must solve for s'(0)

Answer 8

s'(0)=-32(0-2)
s'(0)=-32(-2)
s'(0)=64

Answer 9

Good!

Answer 10

What about C?

Answer 11

I don't know how long the ball takes to reach it's highest point

Answer 12

sorry i mean u must do
s'(t) = 0
to see at what time it will be 0 velocity