How do you solve a definite integral with a square root? Such as, SquareRoot(9-x^2) from -3,0.

Question

anonymous · Answer

Has the teacher taught integration by substitution?

anonymous · Answer

well the whole problem is 4+SquareRoot (9+x^2) from 0,-3. And I know when there are is addition you separate the problem into two. but I am unsure of how to solve the SquareRoot part. Yes he has taught substitution. but this problem is not from our substitution section.

anonymous · Answer

Okay...from my understanding..Let u = (9 + x^2). Now SqaureRoot is the same as u^(1/2)
. Intergrate and get (1/2)u^(3/2) or (1/2) (9 + x^2)^(3/2). Then evaluate

dan815 · Answer

trig sub!

dan815 · Answer

because it is in form 3^2-x^2

anonymous · Answer

why is trig incorporated?

dan815 · Answer

because you were thinking of positive thoughts

anonymous · Answer

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