Rewrite with only sin x and cos x. cos 3x
I got to cos(2x+x)= cos2xcosx-sin2xsinx
thats a great start... so now you need to look at cos(2x) and sin(2x) sin(2x) = 2sin(x)cos(x) and cos(2x) = cos^2(x) - sin^2(x) or one of the other variations. and substitute and simplify
(cos^2x-sin^2x)(cosx)-(2sinxcosx)(sinx) ?
well done... now its just a case of distributing... for the answer..
(cos^3x-sin^2xcosx)(2sin^2xcosx) ?
almost you need a - sign and then collect like terms \[\cos^3(x) - \sin^2(x) \cos(x) - 2\sin^2(x) \cos(x)\] so just collect the like terms
cos^3x-3sin^2xcosx ?
yes, that's it... well done
But that's not one of my choices. cos x - 4 cos x sin2x -sin3x + 2 sin x cos x -sin2x + 2 sin x cos x 2 sin2x cos x - 2 sin x cos x
ok... so look at \[\cos^3(x) = \cos^2(x) \times \cos(x)\] and \[\cos^2(x) = 1 - \sin^2(x)\] so you have \[(1 -\sin^2(x))\cos(x) - 3\sin^2(x)\cos(x)\] and then simplify
So the answer is cosx-4sin^2xcosx ! Thank you so much!
yes, thats the answer thats ok... sorry for the long approach... the solution may have been quicker by choosing a different substitution for cos(2x) but glad to help
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