Question

6(x + 3)2 = 15(x + 3) - 6

Which of the following is a solution for x?

Answer 1

Is it \[ 6(x+3)^2=15(x+3)-6\]

Answer 2

yes thats what i put @BlackLabel

Answer 3

So its being raised to a power? @kaylahhh3

Answer 4

@tHe_FiZiCx99 yes I guess, my options are
x = -1
x = -5
x = 5/2
x = -3

Answer 5

\[\huge 6(x+3)^2 = 15(x+3) - 6\]
\[\huge 6x^2 + 36x + 54 = 15x +39\]
\[\huge 6x^2 + 21x + 15\]
Using the quadratic formula..
\[\huge x = \frac{ -21 \pm \sqrt{21^2 - 4(6)(15)} }{ 2(6) }\]
\[\Huge x = \frac{ -21 \pm \sqrt {441-360} }{ 12 }\]

Answer 6

\[\Huge x = \frac{ -21 \pm \sqrt{81} }{ 12 }\]
\[\Huge x = \frac{ -21 \pm 9 }{ 2 }\]

Answer 7

\[\Huge x = \frac{ -21 + 9 }{ 12 } = -1\]
\[\Huge x = \frac{ -21 - 9 }{ 12 } = \frac{ -30 }{ 12 } = \frac{ -5 }{ 2 }\]
\[\Huge So~x= -1, x= -\frac{ 5 }{ 2 }\]

Answer 8

That was a typo in the second part
\[\huge x = \frac{ -21 \pm 9 }{ 12 }\]
not over 2 *