Given the function f(x) = 0.5(3)^x, what is the value of f−1(7)?
First find the inverse.
\(\bf f(x) = y= 0.5(3)^x\qquad inverse\implies x= 0.5(3)^y\) solve for "y"
i have no idea how to do this i need some explaining :(
notice, all you do is swap the variables about, to get the inverse
oh okay i understand
what do i need to do now? @jdoe0001
so now i have x= 0.5(3)^y how do i find the value of f^−1(7)?
hmm... have you cover logarithms yet?
no, just exponential functions..
hmm... well.... then maybe that's all, you leave it as exponential because to solve for "y", it'd end up as a logarithmic function
okay, thats it?
I'd think so, yes :)
that not one of the options :/
Given the function f(x) = 0.5(3)x, what is the value of f−1(7)? 0.565 1.140 1.771 2.402
hmmm so what are your choices?
ohhh... wait.. your options will be just a value... however... to get that value, you'd need the logarithmic function, which you haven't covered
okay thanks :) ill try and figure it out
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