How do I solve this (if the area does cross the y-axis)? I need to find the area of the shaded area (area between the following two functions):

upper boundary: y= 4-3x
lower boundary: y = 3x^2 - 3x +1

Thank you!

Question

How do I solve this (if the area does cross the y-axis)? I need to find the area of the shaded area (area between the following two functions):

upper boundary: y= 4-3x
lower boundary: y = 3x^2 - 3x +1

Thank you!

anonymous · Answer

First set 
4-3x = 3x^2 -3x +1
to get your intercepts. Once you know the x values you can sub them into your definite integral.

anonymous · Answer

Your second step will look like this:
$$\int\limits_{-1}^{1} (4-3x) - (3x^2-3x+1) dx$$

anonymous · Answer

Good luck!

anonymous · Answer

Yay! I get (2) - (-2) = 4 ae. Thank you!!