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OpenStudy (anonymous):

how many mole of water will be formed starting with 45.00 moles of Alminium hydroxide and excess sulfuric acid. 2Al(OH)3 +3H2SO4=Al2(SO4)3+6H2O

OpenStudy (anonymous):

divide by the ratio of what you have and multiply by what you want to find so 45.00/2 - 22.5, then 22.5 x 6 = 135 ..so you would form 135moles of water

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