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Trigonometry 7 Online
OpenStudy (anonymous):

cosxsinx+sinx=0 find all solutions in interval [0,2π]

OpenStudy (anonymous):

Factor out sinx: sinx(cosx+1)=0 sinx will be zero twice on that interval (at 0 and pi) cosx will equal -1 once at pi. Therefore, the solution seems to be 0 and pi.

OpenStudy (anonymous):

Oh, and 2*pi should be included in that as well since sinx equals zero there.

OpenStudy (anonymous):

thanks

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