Question

cosxsinx+sinx=0 find all solutions in interval [0,2π]

Answer 1

Factor out sinx: sinx(cosx+1)=0
sinx will be zero twice on that interval (at 0 and pi)
cosx will equal -1 once at pi.
Therefore, the solution seems to be 0 and pi.

Answer 2

Oh, and 2*pi should be included in that as well since sinx equals zero there.

Answer 3

thanks