Question

I'm having some trouble Balancing some equations, help? :)

Answer 1

C3H8 + O2 (arrow) CO2 +H2O

Answer 2

C3H8+ 502 -> 3CO2 + 4H20

Answer 3

Okay. Thanks the O was giving me trouble. Is there anyway you can still explain to me why 5 balances it? I'm looking over it and I still don't quite get it. I want to understand

Answer 4

yep okay so im assuming you knew how to do the carbon and the Hydrogen. there are two compounds that contain oxygen as a product. since carbon is three and you put three for CO2 to balance then your oxygen is 6 because 3X2 = six. ex. 10CO2 would be 20 oxygen atoms. then 4 oxygens for hydrogen which means 4 oxygen atoms. add the two together and you get ten . 6+ 4 = 10. then you have to make sure that the O on the reactant is equal to the product so..... five times two is ten

Answer 5

Yeah okay. Thanks for going through all that typing for me :) I think I got the last two I was stuck on thanks to the first problem you helped me with. Can I post them here and you can check them to see if I got it?

Answer 6

u got help :)

anyway nice answer @dareintheren

Answer 7

Okay! 3KNO3 (arrow) 2KNO2 + O2
N2O5 + H2O (arrow) 2HNO3

Answer 8

Is ur eqs like this :-


\[\Large{\color{green}{3KNO_3}\rightarrow \color{red}{2KNO_2+O_2}}\]


\[\Large{\color{blue}{N_2O_5+H_2O}\rightarrow \color{orange}{2HNO_3}}\]

Answer 9

Yes! Right on!

Answer 10

In the second eq u r right

Answer 11

Okay so so how do I fix the other one?

Answer 12

It's those crazy Oxygens i tell ya!

Answer 13

I will tell u the right balanced equations :-


\[\Large{\color{green}{2KNO_3}\rightarrow \color{red}{2KNO_2+O_2}}\]

Answer 14

Got it

Answer 15

?

Answer 16

So there are 6 Oxygens on the left side and there are 4+2 oxygens on the right... Yeah, yeah I got it. Thanks!

Answer 17

Yeah

We got the right answer :-

\[\LARGE{\color{gold}{\checkmark}}\]

Answer 18

\[\LARGE{\color{gold}{\star}}\]

HAPPY Christmas !!!!!



But I m from INDIA

know this country ??

Answer 19

reply plz