Question

help with Fall 2013 midterm exam, i´m really lost.

Answer 1

Hi
What question have the problem;

Answer 2

Hi, the first problem is in q1 with Thevenin and Norton.
I use R3 and R4 as parellel resistences and R1 and R2 as series resistances using I=V/R and it´s says that it´s incorrect.

Answer 3

I have some answers,if somebody needs.
q7.3: 1
q5.1(test): 1
q4.2(test): 4
q4.3(test): 3
q3.3: 1

Answer 4

I think we should shorts the voltage source, so we have R1 and R3 parallel and parallel R2 and R4 = R1 and R3 in series with P2 and P4.

Answer 5

still not getting the answer :(
do you have any equation for this ?

Answer 6

please give me a valid equation because I have only last attempt.

Answer 7

Sorry, i can not verify anything because I do not participate in the lesson MIT 6002x, a friend sent me a pattern and asked me.
If the pattern is correct then (R1 | | R3) + (R2 | | R4)

Answer 8

Hi
Here is the circuit for this problem.
Now please help me to solve this.

Answer 9

q3.1 : 3

Answer 10

q5.2 :0.5
q5.3 :0.5
q5.4: 2

Answer 11

q1.2 =2.7302013422818794

Answer 12

Hi
sineder - q1.2 =2.7302013422818794
Equation give us, we have different values ​​in resistors.

Answer 13

R1+R2//R3+R4

Answer 14

This R1+R2//R3+R4 for Figure 2 ok? And Q1.1 Norton.

Answer 15

Figure 1 οχι 2

Answer 16

ok

Answer 17

You have IN ?

Answer 18

I think it is (R1 | | R3) + (R2 | | R4) for Q1 2 Rth but not R1+R2//R3+R4

Answer 19

Thats what i did and gave me correct

Answer 20

Yes, the same effect comes with both equations.

Answer 21

Yes ideed

Answer 22

Hey but what about the Q1.1 (Norton) ??

Answer 23

hi wat about q1.1 and how to come with q1.3.please explain

Answer 24

What´s the meaning of | | in the ecuation (R1 | | R3) + (R2 | | R4)?

Answer 25

'||' means parallel and '+' means series.

Answer 26

HI @neelshah did u get ans for q1.1 and q1.3

Answer 27

Thanks

Answer 28

hey guys pls help in question 2 and 7.1 and 7.2

Answer 29

hi @andy i just found answers for q2.2:0.4
q2.3: 1.8
q2.4:0.8

Answer 30

can anybody tell me about Q6.(2)??

Answer 31

thanks @ASHWIN. @vasw 6.2 has been removed

Answer 32

u r welcome @andy8

Answer 33

Hey guys what about Q1.3 and Q2.6 ??

Answer 34

Q2 6) -2

Answer 35

Thanks @vasw .
What about Q1.3 ??

Answer 36

I got wrong with this result!

Answer 37

anybody done on q1.3? need help

Answer 38

Anybody find the value of Q1.3 ??