Question

Question 2.2. Solve the given system, using the substitution method.

y = 4x – 6
8x – 2y = 14

(Points : 1)
(14, 12)
(12, 14)
There are an infinite number of solutions.
There is no solution.


Question 3.3. Solve, using the substitution method.

2x + 3y = 1
y = x – 8

(Points : 1)
(0, –8)
(2, –6)
(4, –4)
(5, –3)

Answer 1

y = 4x – 6 <-- plug in this one into
8x – 2y = 14 <-- this one
=> 8x - 2(4x - 6) = 14
=> 8x - 8x + 12 = 14
12 = 14 <-- no solution

Answer 2

2x + 3y = 1
y = x – 8 <-- plug in this one, into above one
so 2x + 3(x-8) = 1 distribute
2x + 3x - 24 = 1 add like terms
5x - 24 = 1 add 24 to both sides
+24 +24
5x = 25 divide both sides by 5
/5 /5
x = 5 <-- which option had that number in it?