What is the oblique asymptote of the function f(x) = the quantity of x squared plus 6 x plus 10, all over x plus 2? Will someone please help me with this problem?

Question

sarahezzmck · Answer

@kewlgeek555 ??

sarahezzmck · Answer

y = x + 1

 y = x - 1

 y = x + 4

 y = x - 4

sarahezzmck · Answer

@campbell_st ?

sarahezzmck · Answer

@Isaiah.Feynman

phi · Answer

It is difficult to read equations typed out as words. Use the equation editor (see button at the bottom of the input area)
$$ f(x) = \frac{x^2+6x+10}{x+2}$$

sarahezzmck · Answer

oh I forgot about that but yes that is the equation. I'm sorry, I just totally forgot :(

phi · Answer

to find the asymptotes,
divide x+2 into x^2 +6x + 10
Can you do that ?  what do you get ?

sarahezzmck · Answer

$$x ^{3}+3x+5$$  ?

sarahezzmck · Answer

Wait theres no x in 3x its just 3

phi · Answer

when you divide, you get a smaller polynomial See this https://www.khanacademy.org/math/algebra/multiplying-factoring-expression/dividing_polynomials/v/polynomial-division for how to do it.

sarahezzmck · Answer

ok thank you :)

phi · Answer

you should get
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