Question

Multiply each pair of conjugates.

Answer 1

\[(2\sqrt{6}+8)(2\sqrt{6}-8)\]

Answer 2

\((a+b)(a-b)=a^2-b^2\) and so \[(2\sqrt{6}+8)(2\sqrt{6}-8)=(2\sqrt6)^2-8^2\] is a start

Answer 3

\((2\sqrt6)^2=4\times 6=24\) and \(8^2=64\) so you will get
\[24-64=-40\]

Answer 4

Oh, okay. I tried looking at the examples in my book but there weren't any like this problem. Thank you!