a+b-c-d=2, 2a-3b+c+d= -2, a-b+c+2d=1, a+b-2c+d=-4 solve the system using augmented matrices
can you write out the matrix?
1 1 -1 -1 2 2 -3 1 1 -2 1 -1 1 2 1 1 1 -2 1 -4
now make the \( a_{21}\) = 0 , what should you do?
|dw:1386298952693:dw|
to make it = 0, we time (-2) to row 1 and then add it to row 2 what do you get Oh, it takes a long time to do, but if you are willing to study, I 'll help. if you don't want, I give you the answer, just 30 seconds . Pick the option, study or answer?
answer
a = 2 b = 3 c = 4 d= -1
I want to know how did u solve it using augmented matrices
Solving an augmented matrix is the same as a regular matrix. You just draw a vertical line and include the last column (with 2,-2, 1, -4). You can do row operations on them. You can switch rows. You can add multiples of one row to another and replace it with the new row. You keep going until you have it in echelon form or reduced row echelon form. It's kind of hard to explain. Learn how to do easy ones first.
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