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a circular plate of metal is being heated in an oven. its radius is increasing at a rate of 0.017 inches/hour. at what rate is the plate's area increasing when its area is 1600π square inches?
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A = pi. r2 Differentiate wrt time
Find r from the area A = pi r^2 Find circumference C = 2 pi r For small fractional changes, the area will increase as (C) (dr/dt), where dr/dt is the rate at which the radius is increasing.
I'm sorry i am confused! ):
Simpler approach: Fine r from A = pi r^2. After an hour r will be 0.017 in bigger. Calculate the new area from A' = pi (r + 0.017)^2 Change in A per 1 hour is A' - A. That's the rate.
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