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Calculus1 19 Online
OpenStudy (anonymous):

Do I have this question right?

OpenStudy (anonymous):

OpenStudy (anonymous):

no

OpenStudy (anonymous):

Okay I must have done something wrong

OpenStudy (anonymous):

have you gotten to derivatives yet?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

then you should recognize this as the derivative of \[f(x)=\sqrt[3]{x}\] at \(x=8\) in other words, if \[f(x)=\sqrt[3]{x}\] then \[f'(8)=\lim_{h\to 0}\frac{\sqrt[3]{8+h}-\sqrt[3]{8}}{h}\]

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