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Geometry 8 Online
OpenStudy (anonymous):

in the triangle ABC;AB=AC and angleA:angleB=8:5;find the angleA.

OpenStudy (kc_kennylau):

|dw:1386420165189:dw|

OpenStudy (kc_kennylau):

Remember the sum of the angles in a triangle?

OpenStudy (anonymous):

yaa 180 degrees

OpenStudy (anonymous):

this sum answer isdegrees

OpenStudy (anonymous):

80 degrees

OpenStudy (kc_kennylau):

good job :D

OpenStudy (anonymous):

thanks

OpenStudy (kc_kennylau):

no problem :)

OpenStudy (anonymous):

i want answer for another sum.can u help me???

OpenStudy (anonymous):

|dw:1386420977033:dw|in the figure

OpenStudy (anonymous):

GIEN ABOVE,IF AC=AD=CD=BD;FIND ANGLEABC.

OpenStudy (kc_kennylau):

IF AC=AD=CD, ΔADC IS AN EQUILATERAL TRIANGLE AND ANGLEC WILL BE 60

OpenStudy (kc_kennylau):

INSTEAD OF 58 AS DEPICTED

OpenStudy (anonymous):

THAT IS NOT A EQUILATERAL TRIANGLE.THAT IS ISOSCELESS

OpenStudy (kc_kennylau):

YOU SAID AC=AD=CD

OpenStudy (anonymous):

SEE THERE I KEPT LINES ALSO

OpenStudy (kc_kennylau):

YOUR IMAGE AND YOUR DESCRIPTION DO NOT MATCH

OpenStudy (anonymous):

AC=AD=CD=BD

OpenStudy (anonymous):

DEAR SEE ONCE DIAGRAM

OpenStudy (anonymous):

WHICH I SENT TO U

OpenStudy (kc_kennylau):

|dw:1386421552700:dw|

OpenStudy (kc_kennylau):

YOU SAID AC=AD=CD

OpenStudy (anonymous):

|dw:1386421603535:dw|

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