Question

integral x^6 ln(1+x) dx

what is the radius of convergence R ?

Answer 1

It only exists for \(1+x > 0\). That's a start.

Answer 2

is R=1

Answer 3

What would be the point of a "Radius of Convergence" that consisted of only one point?

Answer 4

The integral argument EXISTS for x > -1. Does the integral fail to converge for anything in that Domain?

Answer 5

Have you seen Taylor Series?

Answer 6

yes R=1 is correct .D

Answer 7

That notation allows for ONLY symmetric Radius of Convergence. Not my favorite notation.

Answer 8

ok...S thanks.d