PROBABILITY QUESTION:
15% of children attending kindergarten have not had a measles vaccine. In an class of 20 students, what is the probability that at least one has NOT had a measles vaccine?
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OpenStudy (anonymous):
is it 0.96 which can also b written as 96%
OpenStudy (anonymous):
if that the right answer i will show how i got it
OpenStudy (isaiah.feynman):
Show it
OpenStudy (anonymous):
yes please show steps, thats the right answer
OpenStudy (anonymous):
ok first i found out the probability of getting 0 that have not had a measle vaccine using
nCr *q^n-r*P^r
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OpenStudy (anonymous):
where q= failures and p=success
OpenStudy (isaiah.feynman):
Binomial distribution!
OpenStudy (anonymous):
so the percent of failures is 85% because 15% have had not had a measle vaccine
OpenStudy (anonymous):
but in the equation write them as 0.85 and 0.15
OpenStudy (anonymous):
0.85= failures and 0.15=success, n=20 r=0
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OpenStudy (anonymous):
when u plug in everything and u get 0.038759531
OpenStudy (anonymous):
okay makes sense so far
OpenStudy (anonymous):
then u would use a equation i came up with which is No Restriction - What you Dont Want
where NR=1 and WYDW = P(no one who has not had a measle vaccine)
OpenStudy (anonymous):
1-P(0)= 1-0.038759531=0.96
OpenStudy (anonymous):
does that make sense?
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