2. Factor f(x) = x4 + x3 – 8x2 + 6x + 36 completely. Then sketch the graph.
you have to consider the possible rational roots. they will be the positive and negative factors of the constant. then you want to use synthetic division with the factors until you get a remainder of 0. when you find a 0 remainder you know that is a factor. then the numbers left from division make a cubic polynomial. rinse repeat
(x+3)(x+2) = (x^2 + 5x + 6)
are those your two zeros that you have so far?
wait (x+2)(x+3)(x2-4x+6)
that what i got
but i dont know how to graph it
you can factor your quadratic term as well
do you know what the quadratic formula is?
ax2 + bx + c = 0
no here is the quadratic formula \[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
ok
im lost
your quadratic factor. put it into this equation for your last zeros
x^4+x^3-8x^2+6x+36 =x^4 + 2x^3 - x^3 - 2x^2 - 6x^2 -12x + 18x + 36 = x^3(x+2) - x^2(x+2) - 6x(x+2) + 18(x+2) = (x+2) (x^3 - x^2 - 6x + 18) = (x+2) (x^3 + 3x^2 - 4x^2 - 12x + 6x + 18) = (x+2) {x^2(x+3) - 4x(x+3) + 6(x+3)} = (x+2) (x+3) (x^2-4x+6)
i didnt check any of that. but i will help you with the next step \[\frac{ 4\pm \sqrt{(-4)^2-4(1)(6)} }{ 2(1) }\] solve this and you have your next zeros
idk
get as far as you can and ill help you through step by step. you can do the simple arithmatic easily im sure. do you know how to use i yet?
no
first. solve everything under the root. have you gotten that far?
sorry i am not good in math
alight. so (-4)^2 is 16 and -4(6) is -24. so 16-24=-8 correct so you have \[\frac{ -4\pm \sqrt{-8} }{ 2 }\] not you have to use imaginary numbers to get the square root of -8
oh okay
do you know how to simplify radicals?
no but do u time 4 and 8
no you will have \[\frac{ -4\pm \sqrt{8}i }{ 2 }\] then you simplify the radical \[\frac{ -4\pm2\sqrt{2} }{ 2 }\] then you can factor out a 2 to get rid of the denominator
dont forget the i like i did though
u lost me
hm... if you want to graph it just make a t table and just graph it. wherever the graph crosses the x axis is a zero. i dont think i will be able to explain it much further without further confusing you. unless you want me to give it a shot
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