Factor 12x^2-6x-18 must show all work

Question

anonymous · Answer

We can immediately divide this entire equation by 2, to get 2*(6x^2 - 3x - 9)

anonymous · Answer

And 3 incidentally, to get 6*(2x^2 - x - 3), then you can factor the quadratic into two parts, (2x+a)(x+b). Just find a and b, and remember the 6 multiplier, and you have your answer.

anonymous · Answer

@Plastonick Can You Do That In The Equation so I Can Understand it better

anonymous · Answer

Take 6 outside of the equation to get $$6(2x^2-x-3)$$.
Factor the equation in the brackets to get $$6(2x+a)(x+b)$$
Determine the values of a and b, which would satisfy the quadratic part (so two numbers that add together to make -1 and multiply together to make -3). 

Then you have your equation. I won't do all the work for you. :)