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calculus help plz:( pic below
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which one(s)?
5) E
alll 3
oh okay i get why 5 is E now , thanks
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for 4, re-arrange it to a f(x) \[f(x) = y = \pm \sqrt{4 - \frac{ x^2 }{ 4 }}\]
horizontal tangent line means y' = 0. the slope is zero
so its A?
nope. take the first derivative. and you can also look at the graph of the original equation and get/confirm your answer for the first one. draw the points you know and deduce what must be true
take the derivative of x^2 +4y^2=16?
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