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Mathematics 13 Online
OpenStudy (anonymous):

calculus help plz:( pic below

OpenStudy (anonymous):

OpenStudy (anonymous):

which one(s)?

OpenStudy (anonymous):

5) E

OpenStudy (anonymous):

alll 3

OpenStudy (anonymous):

oh okay i get why 5 is E now , thanks

OpenStudy (anonymous):

for 4, re-arrange it to a f(x) \[f(x) = y = \pm \sqrt{4 - \frac{ x^2 }{ 4 }}\]

OpenStudy (anonymous):

horizontal tangent line means y' = 0. the slope is zero

OpenStudy (anonymous):

so its A?

OpenStudy (anonymous):

nope. take the first derivative. and you can also look at the graph of the original equation and get/confirm your answer for the first one. draw the points you know and deduce what must be true

OpenStudy (anonymous):

take the derivative of x^2 +4y^2=16?

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