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Mathematics 22 Online
OpenStudy (anonymous):

Double check my answer? (attached, and ill show my work)

OpenStudy (anonymous):

OpenStudy (raffle_snaffle):

a

OpenStudy (anonymous):

ok so on the first 2 sqrt 28 i know that i have to find the sqrt of 14 x 2 so would i have 7 x 2?

OpenStudy (raffle_snaffle):

yep

OpenStudy (anonymous):

so i cant simplify it anymore im stuck on 7 x 2

OpenStudy (raffle_snaffle):

try 7x4

OpenStudy (anonymous):

ha i see so i would have 2 sqrt 7 for the first

OpenStudy (anonymous):

i think its "a" @raffle_snaffle

OpenStudy (anonymous):

2 sqrt 63 sqrt of 7 x 9 3 sqrt 7 so 2sqrt7 + 3sqrt7 = 5sqrt7? @raffle_snaffle

OpenStudy (raffle_snaffle):

the answer is a

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

or did i have no need to factor at all?

OpenStudy (raffle_snaffle):

i got it figrued out

OpenStudy (raffle_snaffle):

it's been awhile LOL

OpenStudy (anonymous):

on this one i always get them mixed up on the placing, i dont know if 5 goes on the radical or 3

OpenStudy (raffle_snaffle):

use 21x3 for 2sqr63

OpenStudy (raffle_snaffle):

Okay so what I always do is remember what sqr is equal to

OpenStudy (raffle_snaffle):

|dw:1386486125570:dw|

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