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Mathematics 10 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

Directrix (directrix):

Look at the quadrilateral. What is the sum of the interior angle measures of a quadrilateral?

Directrix (directrix):

You know 3 of the 4 angles of the quadrilateral.

OpenStudy (anonymous):

360?

Directrix (directrix):

Yes. So 90 + 90 + 150 + m<P = 360 Solve for m<P

OpenStudy (anonymous):

30?

Directrix (directrix):

The two 90 degree angles come from the theorem: A radius drawn to the tangent of a circle at the point of tangency is perpendicular to it.

Directrix (directrix):

>>>30? That is what I got.

OpenStudy (anonymous):

so.. <APC = 30

Directrix (directrix):

@stupidinmath Correct

OpenStudy (disco619):

This is a Quadrilateral which means it has 4 sides and has interior angles summing up to "360". So the Angle of Tangent from Center of Circle = 90 The Quadrilateral has two tangents = 90+90 And we have been already given the angle = 150 Which makes it... two tangents + given angle - 360 = Unknown Angle 90+90+150-360 = Unknown Angle. I think you can do the rest...

OpenStudy (anonymous):

YAYYYY. Thankss c:

OpenStudy (anonymous):

thank you, too @Disco619 :)

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