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Trigonometry 13 Online
OpenStudy (anonymous):

help please I don't know how to graph it in pi

OpenStudy (anonymous):

OpenStudy (anonymous):

subtraction in domain will cause to slide right side and multiplication will make it expand or contract it

OpenStudy (anonymous):

i know y = 2

OpenStudy (anonymous):

I would start by subbing in: x=-pi x=0 x=pi x=2pi x=3pi x=4pi then the intervals of them, like x=pi/2 To find the x-intercepts, this is when y=0 the maxima and minima are generally the turning points, ie when the derivative=0

OpenStudy (anonymous):

OpenStudy (anonymous):

would it be like that? (red points)

OpenStudy (anonymous):

or the other way?

OpenStudy (anonymous):

well for a start: at x=pi (x axis) y=2cos(pi-(2pi/3)) = 2cos(pi/3) = 1

OpenStudy (anonymous):

so it doesn't shift left or right? just the maxima is raised by 2?

OpenStudy (anonymous):

y=cos(x) goes to y=2cos(x-(2pi/3)) stretched by a scale of 2, translated by +2pi/3 but the question specifically tells you to plot it, by determining the intercepts and stationary points (ie 2 and -2)

OpenStudy (anonymous):

so the ones I attached earlier were both wrong ?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

like this then right,cause its2pi/3

OpenStudy (anonymous):

Yep by the looks of it (quite hard to accurately tell) it looks correct!

OpenStudy (anonymous):

ok cool thank you so much !

OpenStudy (anonymous):

not a problem! :-)

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