Question

simplify the given expression and assume that no variable equals 0.
(19x^-6 y^11)(-6xy^5)

Answer 1

Just multiply them all while using the indices law :)

Answer 2

idk how to do that

Answer 3

Please Help

Answer 4

Huh?

Answer 5

\[\Large\hspace{20pt}(19x^{-6}y^{11})(-6xy^5)\]\[\Large=-6\cdot19\cdot x^{-6}\cdot x\cdot y^{11}\cdot y^5\]\[\Large=-114x^{-6+1}y^{11+5}\]\[\Large=-114x^5y^{16}\]

Answer 6

how did u do that

Answer 7

ok i should have added one more step
\[\hspace{20pt}\Large(19x^{-6}y^{11})(-6xy^5)\]\[\Large=19\cdot x^{-6}\cdot y^{11}\cdot(-6)\cdot x\cdot y^5\]\[\Large=-6\cdot19\cdot x^{-6}\cdot x\cdot y^{11}\cdot y^5\]
Anyway which step was it that you didn't understand? :)

Answer 8

i dont understand none of it

Answer 9

how do u do this

Answer 10

Do you have problem with the first step

Answer 11

yea

Answer 12

I'm just taking out all the factors

Answer 13

and you know the tiny little dot means multiplies?

Answer 14

and 19x^-6 means 19 multiplied by x^-6

Answer 15

So what is it that you don't understand?

Answer 16

i got it now i reakon

Answer 17

all of it?

Answer 18

no

Answer 19

So the second step is just regrouping

Answer 20

yea

Answer 21

And the third step makes use of the laws of indices:
\[\Large x^m\cdot x^n=x^{m+n}\]

Answer 22

wat bout (12x^8 y^9)^3 divided by 8x^9 y ^18)^3

Answer 23

\[\Large\frac{(12x^8y^9)^3}{(8x^9y^{18})^3}\]\[\Large=\left(\frac{12x^8y^9}{8x^9y^{18}}\right)^3\]\[\Large=\left(\frac{12}8\cdot\frac{x^8}{x^9}\cdot\frac{y^9}{y^{18}}\right)^3\]\[\Large=(1.5x^{8-9}y^{9-18})^3\]\[\Large=(1.5x^{-1}y^{-9})^3\]\[\Large=3.375x^{-3}y^{-9}\]\[\Large=\frac{3.375}{x^3y^9}\]
Sorry I have to sleep now please ask others or ask your teachers bye and have a good day