find the surface area of the cone in terms of pi.
can you write down the equation you should use ?
I can put the one I was given...
\[SA=LA+B\]
yes, but what is the equation for LA and for B ?
\[LA=\frac{ 1 }{ 2 }*2\pi(r)*l\]
B is supposed to be the base I think
yes, and what is the formula for the area of the base?
im not sure
the base is a circle. What is the formula for the area of a circle?
oh ok \[A=r^2\]
so \[SA=\frac{ 1 }{ 2 }*2\pi(r)*l+r^2\]
close. when you see "circle" think \(\pi\) Area of a circle = \( π r^2 \) So let's get organized. So far we have \[ SA=LA+B \\ SA= \pi r l + \pi r^2 \]
notice that 1/2 * 2 simplifies to 1 in your LA formula
oj ok I see now
now replace the letters with the numbers (from the figure) can you do that ? Because they want the answer "in terms of pi", (which means leave pi in the answer) we could "factor out" the pi: \[ SA= \pi r l + \pi r^2 \\ SA = (r l + r^2) \pi \] now replace the letters with the numbers (from the figure) can you do that ?
\[SA=((12*18))+12^2)\pi\] \[SA=(216+144 )\pi\]\[SA=360\pi\] that doesnt look right though
@phi
It looks good to me.
my book says it is 144 cm ^2 i dont see how
The question 19 asks for the answer in terms of pi. 144 cm^2 is *not* in terms of pi... so it looks like it is the answer to a different problem.
^^ i forgot the pi part
if the radius were 6, we would get \[ (6*18+ 6*6) π = (108+36)π = 144 π \] so it looks like they are using a radius of 6. The picture *seems* to show the radius is 12... I would say this is a lousy question if they cannot be clear about what is what !
ok so 12 is the diameter then.....!!!thats annoying
Yes. This is supposed to be a course in math, not reading the mind of the goofy questioner.
thanks @phi for clarifying that for me
that makes way more sense
I would show this problem to your teacher, and complain that it is a lousy book. Maybe they will choose a better one next time.
i sent that to her and told her that the book was not clear on what the values were for what she said she would look at it
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