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OCW Scholar - Physics I: Classical Mechanics
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You accidentally throw your car keys horizontally at 8.0 m/s from a cliff 64-m high. How far from the base of the cliff should you look for the keys?
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How long is it in the air (use gravity equation) x 8 m/s (horizontal speed). Force of gravity on earth = 9.8 m/s2.
Horizontal motion and vertical motion are independent
29 m (3.61 s to fall)
Its 28.56 m Here is the explation, As \[ y=u \sin \theta-\frac{ 1 }{ 2 } g t{2} \] where y=-64 (for downward motion), u=8m/s and for horizontal throw, \[\theta=0^{0}\] hence t=3.57s again applying, \[x=u \cos \theta * t\] we have x=28.56m
actually, it us 3.55 seconds
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so the answer is 28.4 meters
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