cos^2(x-pi/4)-3cosx=1
@kirin what do we need to find here?
find x
i think we need to solve \[\cos^2(x-\frac{ \pi }{ 4 })\] first we will use this formula cos(A-B) = cosA cosB +sinA sinB
can you send answer ?
sorry previous approach was wrong we are going to use half angle formulae cos2x = 2*cos^2x-1 it surely gonna give u an answer Sorry i cannot give direct answer here
@kirin we can work step by step u just need to solve with me here
@niksva , does that approach give an exact answer? im not seeing it, this seems to have an numerical approximation solution
This post is too difficult for me.I still do not solve it
yeah it is not giving an exact answer we need to look at other way of solving this problem @dumbcow @kirin do u have any other idea @dumbcow ?
@kirin , is this calculus class?
yes. this is my test
ok you can approximate using newtons method
i will try
\[x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}\] use \[f(x) = \sin(2x) -6\cos(x) -1\]
@dumbcow r u suggesting newton raphson method here?
yes his approximation method for finding zeros
this ques looks complicated
The solutions to this are not nice at all
yeahh it seems one has to play with numbers over here :)
the solutions are irrational
there are 2 solutions within domain 0<x<2pi
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