Question

integral calculus:

y = the integral from -2 to root x of (cos(t)/ t^11) dt

Then dy/dt = ?

Answer 1

@FutureMathProfessor

Answer 2

@calculusxy try this one

Answer 3

Woah... So hard..

Answer 4

which level are you in? College?

Answer 5

Middle school

Answer 6

Nice man I am in college

Answer 7

Great.. Can you help me with my question?

Answer 8

sure tag me in

Answer 9

i think its
\[\frac{dy}{dt} = f(\sqrt{x})\frac{dx}{dt}\]

Answer 10

and what does dx/dt equal to in this case? this is what I am looking for

Answer 11

hmm not sure we have enough info

Answer 12

I checked with webwork the answer is incorret.

The first part says that we should use part 1 of the fundamental theorem of calculus.

Answer 13

since y is given as function of x , to know how y is changing wrt "t" you need to know how x is changing wrt "t"

Answer 14

What I wrote is the only information given. This is what has been dazzling me all day.

Answer 15

\(\huge \dfrac{d}{dx}\int \limits_a^x f(t)dt = f(x) \\ \huge \dfrac{d}{dx}\int \limits_a^{g(x)}f(t)dt =f(g(x))\dfrac{d}{dx}g(x) \)

i think you need dy/dx and not dy/dt ?
because y will be the function of x and not t

Answer 16

oh yes you are right I need dy/dx. I am sorry about that

Answer 17

haha

Answer 18

good, so
it'll just be f(sqrt x) d/dx sqrt x
with f(t) = cos t/ t^11

Answer 19

on webwork it says that dx has no contect this means that its not part of the solution.

Answer 20

dx ?

could you find f(sqrt x) ?
do you how to get d/dx sqrt x ?

Answer 21

if f(t) = cos t / t^11
whats f(sqrt x) ? can u find ?

Answer 22

hey man I entered this into webwork and it says that the answer is equivalent to one that I submitted cos (sqrt(x) ) / (sqrt(x)^11)

Answer 23

but i said, its this :
"f(sqrt x) d/dx sqrt x"

you only input f(sqrt x) part