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Chemistry 16 Online
OpenStudy (anonymous):

How would you solve this? If 1.00X10^-12 moles of cesium 135 emits 1.39x10^5 beta particles in 1 year what is the decay constant.

OpenStudy (aaronq):

i'm not familiar with the decay of caesium atoms, but i'm guessing that it's decay releases a beta particle. Since it's a 1st order decay scenario, you can use this equation: \(\large A_t=A_0*e^{kt}\) \(A_t\)=amount after t time has elapsed \(A_0\)=initial amount k=decay constant t= time

OpenStudy (anonymous):

How would I implement this equation? I know the initial amount and the time elapsed but I don't know the rate constant or the final amount. Would you be able to show me how I would use the equation?

OpenStudy (aaronq):

you're given the final amount, it's given in terms of the emission of \(\beta\) particles.

OpenStudy (aaronq):

\(Atoms_{Cs}-particles_{\beta}=A_t\)

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