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Mathematics 24 Online
OpenStudy (anonymous):

what does this mean?

OpenStudy (anonymous):

OpenStudy (bibby):

The cosine value of some angle theta =0.7673

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

what do I do with the interval given?..

OpenStudy (jdoe0001):

hmm what's the \(cos(180^o)\quad ?\)

OpenStudy (jdoe0001):

the interval given is just a range within which the angle must lie

OpenStudy (jdoe0001):

so say for example... what would be the \(cos(180^o)\quad ?\)

OpenStudy (bibby):

Is there more than 1 angle in this interval?

OpenStudy (anonymous):

oh -1 ?

OpenStudy (jdoe0001):

right.... so now, what's the \(cos^{-1}(-1)\quad ?\)

OpenStudy (anonymous):

isn't it just pi?

OpenStudy (jdoe0001):

yes, pi or \(180^o\) so.. what does that mean? well it means that \(\bf cos(\pi)=-1\qquad cos^{-1}(-1)=\pi\qquad \qquad cos^{-1}[cos(\pi)]=\pi\)

OpenStudy (anonymous):

k go it

OpenStudy (jdoe0001):

\(\bf cos(\theta)=x\qquad cos^{-1}(x)=\theta\qquad \qquad cos^{-1}[cos(\theta)]=\theta\)

OpenStudy (jdoe0001):

so... \(\bf cos(\theta)=0.7673\qquad \textit{take }cos^{-1}\textit{ to both sides}\\ \quad \\ cos^{-1}[cos(\theta)]=cos^{-1}(0.7673)\implies \theta=cos^{-1}(0.7673)\)

OpenStudy (anonymous):

oh!

OpenStudy (anonymous):

so i solve for cos^-1(0.7673)?

OpenStudy (jdoe0001):

yeap, and that'd give you an angle whose cosine is 0.7673

OpenStudy (anonymous):

i got 0.6961... = 0.7 = 40° ? or .. 39.89°

OpenStudy (anonymous):

it sayto round to the nearest hundreths so .69617.. = .70

OpenStudy (jdoe0001):

yeap, I got the same..... so that'd be a value where the cosine is positive, which is in the 1st Quadrant now keep in mind the cosine is also positive in the 4th Quadrant, so the reference angle at the 4th Quadrant is another angle whose cosine function is also 0.7673 |dw:1386537590218:dw|

OpenStudy (jdoe0001):

... to the nearest hundredth then it'll be 39.89 and 360-39.89 = 320.11

OpenStudy (anonymous):

wait so the answer that my question wanted wasn't in degrees or is it since thetha?

OpenStudy (anonymous):

ok yeah i see :)

OpenStudy (jdoe0001):

well... it doesn't specify, but you can always convert to radians if you wish, by \(\bf radians=\cfrac{degrees\cdot \pi}{180}\)

OpenStudy (anonymous):

k ty

OpenStudy (jdoe0001):

yw

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