Calculate the Cell Potential and Delta G^0 for the following reaction that takes place in an Electrochemical cell at 25C. Al(s) / Al 3+ (aq, 0.515M)//Al3+ (aq,3.98M)/ Al(s)
@Data_LG2 @robtobey @timo86m Can either of you please help me with this problem please? Thank you for reading this.
sorry, i don't know how to do this :/
okay, thank you @Data_LG2
@radar @timo86m @Luigi0210 Could any of you please help me understand and solve this problem please? I thank you for taking the time to read this. I am confused as to where to start. But I know the Log of Q or K is going to be products/reactants. so, Al (s)/ Al3+ (aq,0.515M) // Al 3+ (aq, 3.89M)/ Al(s) it would be \[\frac{ 3.89M }{ 0.515M } = 7.55\] And as to the rest I dont remember how to solve for the cell potential.
@jim_thompson5910 do you think u could help me please :/
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