given the function f(x) = x^3+2x^2-3x-5 what is resulting function when f(x) is shifted to the right 1 unit
@frogs29 @douglaswinslowcooper
@ganibl
Shifted to the right one unit. g(x) = f(x-1), substitute (x-1) for x in f(x) to get g(x). e.g., f(x) = m x + b f(0) = b g(x) = m (x-1) + b g(1) = b Old f values now occur for g(x) at x+1. Shifted one unit to the right.
No idea whats happening here @douglaswinslowcooper
Given equation f(x) = x^3+2x^2-3x-5 It is shifted by 1 unit which means we need to calculate f(x + 1)
f(x + 1) = (x + 1)^3 + 2 (x + 1)^2 -3(x + 1) - 5 x^3 + 3x^2 + 3x + 1 + 2(x^2 + 2x + 1) -3x - 3 - 5 x^3 + 3x^2 + 3x + 2x^2 + 4x -3x -5 x^3 + 5x^2 +4x - 5
The resultant equation will be x^3 + 5x^2 + 4x - 5 when f(x) is shifted by one unit to the right
Oh wow.. Yes much better thank you!!! can youhelp with another please?
Sure
Calculate the average rate of change for the function f(x) = x^4 + 3x^3 -5x^2 + 2x -2. From x=-1 to x=1
@ganibl
anything?
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