A bucket of water with total mass 23 kg is attached to a rope, which in turn is wound around a 0.050-m radius cylinder at the top of a well. The bucket is raised to the top of the well and released. The bucket is moving with a speed of 8.0 m/s upon hitting the water surface in the well. What is the angular speed of the cylinder at this instant? The answer is 39 rad/sec but I am not sure how to get that answer
do you have picture for this problem?
No
sorry I could not understand the problem. is that exactly how it is written?
rope needs to have same speed along its length, that means at the point where rope meets the cylinder the cylinder has same speed, from \[v=\omega r\] \[\omega=v/r=8m/s/0.05m=160rad/s\]
Yeah that's exactly how its written....thanks anyway
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