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Mathematics 15 Online
OpenStudy (anonymous):

Find the derivative. Assume a and b are constants: Q=2aP^3+6bP^2 dQ/dP = _______ I think the constants are throwing me off...

OpenStudy (anonymous):

6p^2 + 12p

OpenStudy (anonymous):

I actually already tried that ^ It's wrong.

OpenStudy (anonymous):

\[\frac{ dQ }{ dP }=6aP^2+12bP\]

OpenStudy (anonymous):

he forgot the constants a and b

OpenStudy (anonymous):

That's wrong too D':

OpenStudy (anonymous):

The answer is 0

OpenStudy (anonymous):

Since a and b are constants and derivative of constant is 0 the whole term will be 0

OpenStudy (anonymous):

Oh, nevermind, I accidentally didn't capitalize a P. I'm an idiot. Thanks though!

OpenStudy (anonymous):

@ganibl it cannot be zero If \[y=3x^2 \] then \[\frac{ dy }{ dx }\neq 0\] it is \[6x\]

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