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Find the derivative. Assume a and b are constants: Q=2aP^3+6bP^2 dQ/dP = _______ I think the constants are throwing me off...
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6p^2 + 12p
I actually already tried that ^ It's wrong.
\[\frac{ dQ }{ dP }=6aP^2+12bP\]
he forgot the constants a and b
That's wrong too D':
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The answer is 0
Since a and b are constants and derivative of constant is 0 the whole term will be 0
Oh, nevermind, I accidentally didn't capitalize a P. I'm an idiot. Thanks though!
@ganibl it cannot be zero If \[y=3x^2 \] then \[\frac{ dy }{ dx }\neq 0\] it is \[6x\]
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