Question

how do I divide this polynomial?
8y^6-3^2-4y over 4y
please show work

Answer 1

(8y^6-3^2-4y)/(4y) = (8y^6)/(4y) + (-3^2)/(4y) + (-4y)/(4y)

Answer 2

then what?

Answer 3

y^a/y^b = y^(a-b)
(8y^6)/(4y) = 8/4 * y^6/y = 2*y^(6-1) = 2*y^5

Answer 4

I don't get it

Answer 5

http://www.wolframalpha.com/input/?i=8y%5E6-3%5E2-4y+%2F+4y

Look at the step by step. Sorry I'm doing homework myself. :/

Answer 6

1. y^a/y^b = y^(a-b)
2. (8y^6)/(4y) = 8/4 * y^6/y
3. y^6/y=y^5
4. 8/4 * y^6/y = 2*y^5
which step is confusing?

Answer 7

just the way youre typing it

Answer 8

I don't get it