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Mathematics 16 Online
OpenStudy (azureilai):

I am stuck on an exponential decay/log question. Question and work attached. I have no idea how to go further in my work.

OpenStudy (azureilai):

OpenStudy (anonymous):

no wonder you are stuck they are using an \(a\) instead of \(e\) which is what you were trying to solve \[B=B_0e^{kt}\] but they only asked for \[B=B_0a^{kt}\] which actually makes it much easier

OpenStudy (anonymous):

if you want to use any base, rather than \(e\) you can use \(\frac{200}{500}=\frac{2}{5}\) and write your formula as \[B=500\left(\frac{2}{5}\right)^{\frac{t}{2}}\] as your population decreases to \(\frac{2}{5}\) of its original amount every two hours

OpenStudy (anonymous):

you only need to find the \(k\) using the log as you did, if you are asked to find the equation in the form \[B=B_0e^{kt}\] in which case \(B_0=500\) and you solve for \(k\) via \[\ln(\frac{2}{5})=2k\] making \[k=\frac{\ln(\frac{2}{5})}{2}\]

OpenStudy (azureilai):

Oh ok. that makes it easier. I was having a hard time solving it since there was two unknowns and I got confused. Thanks for the explanation.

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