Question

One more square root Q... I think...
How would I do: square root of 162/y^6

Answer 1

do you know what \(\sqrt{y^6}\) is ? by now it should not be hard

Answer 2

as for \(\sqrt{162}\) you should think of \(162\) as \(81\times 2\) and then finding \(\sqrt{162}\) should also be easy
let me know if you still need help

Answer 3

I'm so confused b/c there isn't a number times itself that equals 6, and I don't know how I would set it up... I'm sooo confused. I know I should know this, but it's just not sticking with me. Thanks for your patience with my stupidity hahaha! <3

Answer 4

the 6 is in the exponent, not in the base
you are not looking for the square root of 6, you are looking for the square root of \(y^6\)
what is half of 6?

Answer 5

3

Answer 6

Haha :)

Answer 7

right
and so what is \(\sqrt{y^6}\) ?

Answer 8

3..???? So y^3 ??

Answer 9

yes

Answer 10

Sooo I am just looking for half of the exponent then? And if it were the cubed root, then it would be...?

Answer 11

how about \(\sqrt{y^{22}}\) ?

Answer 12

if it was the cubed root, it would be ... one third of the exponent

Answer 13

Hmmm... that is where I am confused. If it were y^22, then would it be y^11 with a 2 somewhere??? haha I am so confused :(

Answer 14

if it was \(\sqrt{y^{22}}\) then you get \(y^{11}\) that is all

Answer 15

I think it is coming to me! Thank you!! So if it were the cubed root of y^22...?

Answer 16

if it was \(\sqrt{y^{23}}\) then you would get \(y^{11}\sqrt{y}\) because 2 goes in to 23 11 times with a remainder of 1
and it it was \(\sqrt[3]{y^{22}}\) then it would be \(y^7\sqrt[3]{y}\) becuase 3 goes in to 22 7 times with a remainder of 1

Answer 17

Brilliant! Thank you thank you thank you! Life saver.

Answer 18

it is not too hard when you get the hang of it.
try some and see
good luck on your exam

Answer 19

I had a hang of it a week ago, but then I had a huge break and I always forget. Thank you - I will need all the luck I can get! Soooo worried haha.