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Solve the integral sqrt(x)-2 from [1,9]
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\[\int\limits_{1}^{9}\sqrt(x)-2*dx\]
\(\sf \color{red}{\sqrt{x} = x^{\frac{1}{2}}}\)
\[\int_1^92dx=8\times 2\] is a start
Then use the fundamental theorem of calculus pt. II to solve. Which is F(b)-F(a)
what, lord abb0t said.
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|dw:1386564070164:dw| My face when you said that
Kk let me quickly do the work.
chop-chop!
(4/3)?
\[\large \int\limits_{1}^{9} x^{\frac{ 1 }{ 2} } - 2~dx\] \[\Huge \int\limits_{1}^{9} \frac{ x^\frac{ 3 }{ 2 } }{ \frac{ 3 }{ 2 } } - 2x\]
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\[\Huge \int\limits_{1}^{9} \frac{ 9^\frac{ 3 }{ 2 } }{ \frac{ 3 }{ 2 } } - 2(9) - (\frac{ 1^{\frac{ 3 }{ 2 }} }{ \frac{ 3 }{ 2 } } - 2(1))\]
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