Question

A shuffleboard disk of mass 0.50 kg accelerates under
an applied force of 12.0 N [forward].
(a) If the magnitude of the frictional resistance is
8.0 N, find the magnitude of the disk’s acceleration.
(b) If the disk moves from rest for 0.20 s, how far does
it travel while accelerating?

For a) I got 8.0m/s^2 and i'm pretty confused on how to do b. Do I use the acceleration I got for question a or do I find it again?

Answer 1

The answer is 0.16m

Answer 2

So your pretty much there once you got the acceleration done. To find part B all your doing is using the kinematic equations you learned to solve for the distance moved in .2 seconds. You know that you have the initial distance, let's set it equal to zero, initial velocity, it is also zero, you have time and acceleration this leads to the use of \[x = x _{0} + v _{0}*t + \frac{ 1 }{ 2 }*a _{x}*t ^{2}\] from here you just plug and chug to get .16 meters.

Answer 3

It's the same equation as:
\[\Delta d = v _{f} \Delta t - a _{av}(\Delta t)^2 / 2\]
right?

Answer 4

It looks the same, I'm assuming that that formula came from your physics textbook so it should work the same way.