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cos(-11pi/4) sin(-11pi/4)
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\[\cos(a+k2\pi)=\cos(a) \]\[\sin(a+k2\pi)=\sin(a) \] for all integers k
So basically you can factor out multiples of 2 pi
yeah, i tried that i thought the exact value of cos what square root 3 and sin was 1/2
are you asking\[\cos(-11\frac{ \pi }{ 4 })\]or\[\cos(\frac{ -11\pi }{ 4 })\]
-11pi/4
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That doesn't clarify. Is it (-11 pi)/4 or -11 (pi/4)
(-11 pi)/4
So you subtract 2pi from that and what do you get?
Sorry add 2pi
13pi/4
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\[\frac{ -11\pi }{ 4 }+2\pi=\frac{ -11\pi }{ 4 }+\frac{ 8 \pi }{ 4 }=\frac{ -3 \pi }{ 4 }\]
These are some values to remember:\[\cos (\pi/4)=\sin (\pi/4)=\frac{ \sqrt{2} }{ 2 }\] so that is for a 45 degree angle in quadrant I
Which quadrant does (-3/4)pi lie in?
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