Question

1.)The graph of a line has a slope of -3 and passes through the point (-6,-4). What is the equation of the line in point-slope form?

y+4=-3(x+6)
y-4=-3(x-4)
y-6=-3(x-4)
y+6=-3(x+4)

2.)What are the x- and y-intercepts of the line?
2x-3y=-12

x-intercept 6, y-intercept -4
x-intercept-6, y-intercept 4
x-intercept-4, y-intercept 6
x-intercept 4, y-intercept -6

Answer 1

@Annie96 ...The standard form of a straight line in point-slope form is:
\[y-b=m(x-a)\]
for a point (a,b) and slope m...Can you plugin you values above and show me your work?

Answer 2

2(6)-3(-4)=12

Answer 3

Nope...for your first question, point=(a,b)=(-6,-4)
and slope=m=-3
so plugin these values in the standard equation of straight line:
\[y-b=m(x-a)\]

Answer 4

-4+4=-3(-6+6)

Answer 5

no you're putting (x,y)=(-6,-4) as well...they're general variables...(x,y) could be any point on the line...
it should be :
y+4=-3(x+6)

Answer 6

ok.

Answer 7

If you want to know more about how STANDARD FORM of equation for straight line is derived:
http://www.mathsisfun.com/algebra/line-equation-point-slope.html
or you could post another question

Answer 8

About your second question:
Hint:
i) X intercept is the value of x at which the line cuts the x-axis i.e y=0 for X-intercept
ii) Y intercept is the value of y at which the line cuts the y-axis i.e x=0 for Y-intercept
so can you guess your x and y intercepts

Answer 9

x-intercept-6, y-intercept 4

Answer 10

That's right

Answer 11

Thank you so much for you're help.

Answer 12

oh no problem