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simplify z^2-4/2z^2+5z+2 x 2z^2+z/z-2
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It's this, correct? \[\LARGE \frac{z^2-4}{2z^2+5z+2}*\frac{2x^2+z}{z-2}\]
yes
no 2z^2+z on the right
Oh, sorry. But start off by factoring.
these are my options 1. 2z^2/5z 2. 2z^2+z/2z+1 3. z 4. 1/z 5. none
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i dont need to show work on them
Still, it's a good thing to do so.. it helps when they get lengthy and complicated..
aww man im kind of in a rush lol
Well okay.. first write it out: \[\LARGE \frac{z^2-4}{2z^2+5z+2}*\frac{2z^2+z}{z-2}\] Now factor: \[\LARGE\frac{(z-2)(z+2)}{(2z+1)(z+2)}*\frac{2(z+1)}{z-2}\] Now just cross cancel and simplify.. pretty simple
On the top right, that should be z(2z+1) not 2(z+1)
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thanks man
Anytime!
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