I know the answer is 3 I just can't figure out how they got it :p

Question

anonymous · Answer

$$9\sqrt{13a-3}=54$$

amistre64 · Answer

divide, square, add, then divide again

anonymous · Answer

Divide what?

amistre64 · Answer

these are basic and fundatmental algebraic techniques ...

9x = 54,  what would you divide to find x?

amistre64 · Answer

...

anonymous · Answer

You'd divide 54 by 9 in order to find x

amistre64 · Answer

good, then x = 54/9 = 6

move to the next "portion"

sqrt(x) = 6

how would we determine an x for this?

anonymous · Answer

There's no x in the problem? nd the variable is under the square root symbol?

amistre64 · Answer

im taking you thru the steps that you would do if you had seperate problems

amistre64 · Answer

how would you solve sqrt(x) = 6 ?

anonymous · Answer

Idk

amistre64 · Answer

divide, square, add, then divide again

we already divided off the 9, the next process is to ?

anonymous · Answer

Take the square root of x?

amistre64 · Answer

almost, take the sqaure of sqrt(x)  and the square of 6

x = 6^2 = 36

amistre64 · Answer

now we are left with:  13x - 3 = 36

how would we complete this process?

anonymous · Answer

wolf will you finish typing already? nd Then you add?

amistre64 · Answer

9  sqrt(13-3) = 54
\9                     \9
-----------------
  sqrt(13a - 3) = 6  , square each side

  13a - 3 = 36 

etc ...

amistre64 · Answer

yes, what do we add?