The angle through which a rotating wheel has turned in time t is given by \(\theta = 8.5t-15.0t^2+1.6 t^4\) where \(\theta is in radians and t in seconds. . What is the average angular velocity , and the average angular acceleration between t =2.0s and t =3.0s? Please, help
I have to find out \(\theta_3~~and~~\theta2\) then apply formula \(\bar\omega=\dfrac{\theta_3-\theta_2}{dt}\) to find out the average angular velocity. My question is why cannot I use \(\bar\omega = \dfrac{\omega_3-\omega2}{2}\).
Usually, when you find an average of two numbers you add them and divide by 2, is that what you meant @Loser66 ? Like this? $$ \overline \omega=\cfrac{\omega_3+\omega_2}{2} $$
yes
They should be equal.
If it is a continuous function with no discontinuities that go to infinity like this:|dw:1386639047847:dw| Using the calculus technique, you would find that in my sketch, the average would be positive infinity. So it appears that you can use (a+b)/2 for averages if there are no vertical asymptotes.
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