Question

Solve for x.

Answer 1

\[\sqrt{x+3}+\frac{ x^2 }{ 2 }+\frac{ 3x }{ 2 }=0\]

Answer 2

take out \(\dfrac x2\) from the second and third term

Answer 3

so like \[\sqrt{x+3}+\frac{ x }{ 2 }[x+3]=0\]

Answer 4

now what do i do?

Answer 5

wait a sec lemme fink sry

Answer 6

sorry i think that step was useless sorry

Answer 7

its ok, what step should i do then?

Answer 8

1. take the surd to the rhs
2. square both sides
3. realize that you're left with a quartic equation
4. give up

Answer 9

sorry i do not recommend the fourth step

Answer 10

haha, ok. thanks

Answer 11

wait i know how to do it

Answer 12

sorry for wasting such a lot of time

Answer 13

\[\begin{array}{rl}\sqrt{x+3}+\frac x2(x+3)&=&0\\\frac x2(x+3)&=&-\sqrt{x+3}\\\frac{x^2}4(x+3)^2&=&x+3\\\frac{x^2}4(x+3)^2-(x+3)&=&0\\\frac{x^2(x+3)^2-4(x+3)}4&=&0\\x^2(x+3)(x+3)-4(x+3)&=&0\\ [x^2(x+3)-4](x+3)&=&0\\(x^3+3x^2-4)(x+3)&=&0\end{array}\]

Answer 14

How would you factorize a quartic equation lol